SOLUTION: This one has me stumpted! Could someone explain? A cyclindrical aquarium is designed with a base diameter of 5 feet and a height of 6 feet. If 3.14 is used for pie, what is th

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Question 613260: This one has me stumpted! Could someone explain?
A cyclindrical aquarium is designed with a base diameter of 5 feet and a height of 6 feet. If 3.14 is used for pie, what is the approximate volume of the aquarium to the nearest cubic foot.
A. 38
B. 118
C. 471
D. 1,884



Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
This one has me stumpted! Could someone explain?
A cyclindrical aquarium is designed with a base diameter of 5 feet and a height of 6 feet. If 3.14 is used for pie, what is the approximate volume of the aquarium to the nearest cubic foot.
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V = (Area of base)*(height)
V = (3.14*2.5^2)*6
V = 3.14*6.25*6
V is approximately 118 cubic ft.
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Cheers,
Stan H.
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A. 38
B. 118
C. 471
D. 1,884

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 



cyclindrical aquarium is designed with a base diameter of 5 feet and a height of 6 feet.

V = pi%2Ar%5E2h+=+3.14%2A%282.5%29%5E2%2A6 = 118 ft^3, rounded to the nearest whole number