You can put this solution on YOUR website! Write as a single logarithm (including exponents)
log3x-4log y+3log(2a)-log10
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= log(3x) - log(y^4) + log(2a)^3 - 1
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= log[(3x)(2a)^4)/y^4]
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= log[48xa^4/y^4]
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Cheers,
Stan H.