SOLUTION: cube root (8^2x)=sqrt2^(4x-1)

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Question 612970: cube root (8^2x)=sqrt2^(4x-1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
root%283%2C%288%5E%282x%29%29%29=sqrt%282%5E%284x-1%29%29
2%5E%282x%29=sqrt%282%5E%284x-1%29%29
Square both sides
2%5E%284x%29+=+2%5E%284x-1%29
4x = 4x - 1
No solution.