SOLUTION: order of operation on solving questions like this 40+6[5exponent2-(7-2)sqaure root of 16]

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Question 612946: order of operation on solving questions like this

40+6[5exponent2-(7-2)sqaure root of 16]
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
40+6[5^2-(7-2)*sqrt(16)]

40+6[5^2-(7-2)*4]

40+6[25-(7-2)*4]

40+6[25-5*4]

40+6[25-20]

40+6[5]

40+30

70


So 40+6[5^2-(7-2)*sqrt(16)] = 70