SOLUTION: I'm trying to teach myself logarithms and I am having trouble with this problem and would really appreciate it if you could help: {{{ log ( e , x-2 ) = 3 }}} Just in case I d

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I'm trying to teach myself logarithms and I am having trouble with this problem and would really appreciate it if you could help: {{{ log ( e , x-2 ) = 3 }}} Just in case I d      Log On


   

Question 612944: I'm trying to teach myself logarithms and I am having trouble with this problem and would really appreciate it if you could help:
+log+%28+e+%2C+x-2+%29+=+3+
Just in case I didn't enter that right, the problem is: The natural logarithm of (x-2) = 3 and I need to solve for x. I have tried changing the problem into log ( e , x ) / log ( e , -2 ) = 3(log ( e , -2 ) but I'm pretty sure that's wrong. I don't really know what to do. Thanks.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
To make things shorter, we can say ln%28x-2%29 since ln (lowercase L then n) is the natural logarithm (ie log base 'e')

So we can say ln%28x-2%29+=+3

Now solve for x

ln%28x-2%29+=+3

x-2+=+e%5E3

x+=+e%5E3%2B2