SOLUTION: How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol
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Question 612774: How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! How many gallons of an 80% alcohol solution must be mixed with 50 gallons of a 16% solution to obtain a solution that is 70% alcohol
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Equation:
alcohol + alcohol = alcohol
0.80x + 0.16*50 = 0.70(x+50)
80x + 16*50 = 70x + 70*50
10x = 54*50
x = 5*54
x = 270 gallons (amt. of 80% solution needed)
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Cheers,
Stan H.
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