SOLUTION: a square of 400 cm squared has the same perimeter as a rectangle whose length is 8 cm more than its length. find the area of the rectangle.

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Question 612760: a square of 400 cm squared has the same perimeter as a rectangle whose length is 8 cm more than its length. find the area of the rectangle.
Answer by radh(108) About Me  (Show Source):
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We know that to get the area of a square, we use s%5E2=a. In this case, we know the area, not the side. We have to find the side by plugging in what we know and isolating the variable. s%5E2=400. So, to find s, we take the square root of 400 which is 20. Now we know that each side of the square is 20 cm. To find perimeter, you just multiply a side by 4 (in the case of a square). 20%2A4=80. The perimeter is 80 centimeters.

We know that the length is the same as the square's, plus 8. s%2B8. Let's plug in what we know from before: 20%2B8=28. So, the length of the rectangle is 28. What is the width? We know that the perimeter of the rectangle is the same as the square. To find the perimeter of a rectangle, the formula is 2l%2B2w=p. Let's plug in what we know: 2%2828%29%2B2w=80
Simplify: 56%2B2w=80 to 2w=24 to w=12
Now we know that the width is 12 and the length is 28. To find the area, you use this formula: l%2Aw=a. Let's plug in what we know 12%2A28=336

So, the area of the rectangle is 336 cm.