SOLUTION: At noon a horse and buggyheaded north traveling 10 miles per hour. Two hours later, a roadster headed south from the same location driving 50 miles per hour. At which time will the
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: At noon a horse and buggyheaded north traveling 10 miles per hour. Two hours later, a roadster headed south from the same location driving 50 miles per hour. At which time will the
Log On
Question 61272: At noon a horse and buggyheaded north traveling 10 miles per hour. Two hours later, a roadster headed south from the same location driving 50 miles per hour. At which time will the horse and buggy be 140 miles from the roadster? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 140=10T+50(T-2)
140=10T+50T-100
60T=140+100
60T=240
T=240/60
T=4 HOURS
PROOF
140=10*4+50(4-2)
140=40+50*2
140=40+100
140=140