SOLUTION: How do you solve this question? 5^(3x)=25^(2x+1)
The lesson that I am working on is about logarithms, so at some point I figure I need to use the log function or ln, but I don't
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-> SOLUTION: How do you solve this question? 5^(3x)=25^(2x+1)
The lesson that I am working on is about logarithms, so at some point I figure I need to use the log function or ln, but I don't
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Question 612700: How do you solve this question? 5^(3x)=25^(2x+1)
The lesson that I am working on is about logarithms, so at some point I figure I need to use the log function or ln, but I don't know where.
So far this is what I have done... please tell me if I am on the right track. THANK YOU!
5^(3x)=25^(2x+1)
5^(3x)=5^(2(2x+1)
5^(3x)=5^(4x+2)
3x=4x+2
-x=2
x=-2
You can put this solution on YOUR website! 5^(3x)=25^(2x+1)
5^(3x)=5^(2(2x+1)
5^(3x)=5^(4x+2)
3x=4x+2
-x=2
x=-2
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Looks good to me.
check the answer
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