SOLUTION: Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8.

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8.      Log On


   

Question 612623: Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Divide 184 into two parts such that 1/3 of one part may exceed 1/7 of the other part by 8.
-----
Equatiion:
(1/3)x -(1/7)(184-x) = 8
------
Multiply thru by 21 to get:
7x - 3(184-x) = 168
7x - 3*184 + 3x = 168
10x = 168+3*184
10x = 720
x = 72
================
184-x = 112
================
Cheers,
Stan H.
=====================