Question 612620: the sum of a 2 digit number and number formed by reversing the digits is 88 if the digits differ by 2. find the no.
Found 2 solutions by richard1234, MathTherapy:
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! Two ways to do it:
Let the number be 10a+b, where a and b are digits. The "reversed" number is 10b+a, and
 + (10b+a) = 88 \Rightarrow 11(a+b) = 88 \Rightarrow a+b = 8)
Therefore 17,26,35,44,53,62,71 are the only possible integers. 35 and 53 are the only ones that differ by two, so the answer is {35,53}.
The other way to do it is let the number be 10a + (a+2); switching the digits gives 10(a+2) + a. Do the same method as shown above.
Answer by MathTherapy(10552)  (Show Source):
|
|
|
