SOLUTION: I know the answer to this already but I don't know the proper way to solve for it so that is what i'm looking for here.
The hypotenuse of a right triangle is 25m and the differe
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-> SOLUTION: I know the answer to this already but I don't know the proper way to solve for it so that is what i'm looking for here.
The hypotenuse of a right triangle is 25m and the differe
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Question 612610: I know the answer to this already but I don't know the proper way to solve for it so that is what i'm looking for here.
The hypotenuse of a right triangle is 25m and the difference between the lengths of the two legs are 17m what are the lengths of the two sides.
You can put this solution on YOUR website! The hypotenuse of a right triangle is 25m and the difference between the lengths of the two legs are 17m what are the lengths of the two sides.
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Let x = length of one leg
then
x+17 = length of second leg
.
applying Pythagorean theorem
x^2 + (x+17)^2 = 25^2
x^2 + (x+17)(x+17) = 25^2
x^2 + x^2+34x+289 = 625
2x^2+34x+289 = 625
2x^2+34x-336 = 0
x^2+17x-168 = 0
(x+24)(x-7) = 0
x = {-24, 7}
throw out the negative solution (extraneous) leaving:
x = 7 meters (one leg)
.
second leg:
x+17 = 7+17 = 24 meters
