SOLUTION: What is the logarithmic form of the equation: y=20^(-3/2) ? a) -log[-3/2]y=20 b) log[20](-3/2)= y c) log[20]y=-3/2 d) log[3/2]20=y

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: What is the logarithmic form of the equation: y=20^(-3/2) ? a) -log[-3/2]y=20 b) log[20](-3/2)= y c) log[20]y=-3/2 d) log[3/2]20=y      Log On


   

Question 612165: What is the logarithmic form of the equation:
y=20^(-3/2) ?
a) -log[-3/2]y=20
b) log[20](-3/2)= y
c) log[20]y=-3/2
d) log[3/2]20=y
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
What is the logarithmic form of the equation:
y=20^(-3/2) ?
a) -log[-3/2]y=20
b) log[20](-3/2)= y
c) log[20]y=-3/2
d) log[3/2]20=y
..
ans:c) log[20]y=-3/2, which reads: log(y),base 20=-3/2