SOLUTION: Please help. Write the equation of a line, in standard form with the integer coefficiants, that passes through the points (6,7) and (-2,15) PLEASE SHOW ME THE WORK!!!!!!!!!!!!!!!!!

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Question 61194: Please help. Write the equation of a line, in standard form with the integer coefficiants, that passes through the points (6,7) and (-2,15) PLEASE SHOW ME THE WORK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! and how to solve.
-Thanks
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website!
FIRST WE FIND THE SLOPE USING THE TWO POINTAS GIVEN (Y2-Y1)/(X2-X1)
(15-7)/(-2-6)
8/-8=-1 FOR THE SLOPE
NOW REPLACING Y+X IN THE LINE FORMULA (Y=mX+b) WITH -1 FOR (m) & WITH ONE SET OF THE COORDINATES WE GET
6=-7+b AND SOLVE FOR b (THE Y INTERCEPT)
6+7=b
b=13
THIS GIVE US THE EQUATION Y=-X+13 FOR THIS LINE WITH A SLOPE OF (-1)& A Y INTERCEPTOF (13)
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WHAT YOU MAY NEED IS TO GRAPH THESE TYPEOFPROBLEMS USING GRAPH PAPER.
IF YOU DON'T HAVE ANY JUST GO TO ANY STAPLES OR STORE THAT SELLS PAPER PRODUCTS AND GET A PAD OF GRAPH PAPER. DRAW THE X (VERTICLE LINE) & Y (HORIZONTAL) LINE IN THE MIDDLE OF THE PAGE. THEN LABEL THE MANY UNITS TO THE RIGHT OF THE LINE INTERSECTION PLUS X (+X) VALUES, UNITS TO THE LEFT AS MINUS X (-X) VALUES, THEN LABEL THE UNITS ABOVE THE INTERSECTION PLUS Y (+Y)VALUES AND THE UNITS BELOW THE INTERSECTION MINUS Y (-Y)VALUES.
IF YOU NEED MORE HELP GET A GEOMETRY TEXT BOOK FROM THE LOCAL LIBRARY.