SOLUTION: Given three consecutive odd numbers such that the square of the second number is 80 less than the square of the third number. Find those numbers.
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Question 611876: Given three consecutive odd numbers such that the square of the second number is 80 less than the square of the third number. Find those numbers. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Given three consecutive odd numbers such that the square of the second number is 80 less than the square of the third number. Find those numbers.
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
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Equation:
(2x-1)^2 = (2x+1)^2-80
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4x^2-4x+1 = 4x^2 + 4x +1 - 80
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Subtract 4x^2 from both sides:
Add 4x to both sides:
8x -79 = 1
8x = 80
x = 10
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1st: 2x-3 = 17
2nd: 19
3rd: 21
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Cheers,
Stan H.
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