SOLUTION: Please help: I have solved this, but I'm unsure if it's right. ----------- ------ 1/2 log 25 base 6 + log x base 6 = log 20 base 6 --- log 25^1/2 base 6 + log x base 6 = log 2

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Please help: I have solved this, but I'm unsure if it's right. ----------- ------ 1/2 log 25 base 6 + log x base 6 = log 20 base 6 --- log 25^1/2 base 6 + log x base 6 = log 2      Log On


   

Question 611687: Please help:
I have solved this, but I'm unsure if it's right.
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1/2 log 25 base 6 + log x base 6 = log 20 base 6
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log 25^1/2 base 6 + log x base 6 = log 20 base 6
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log 5 base 6 + log x base 6 = log 20 base 6
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5+x=20
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x=15
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Did I do this right?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve
1/2 log 25 base 6 + log x base 6 = log 20 base 6
1/2log6(25)+log6(x)=log6(20)
1/2log6(25)+log6(x)-log6(20)=0
place under single log
log6[√25x/20]=0
convert to exponential form
6^0=√25x/20=1
√25x=20
5x=20
x=4