SOLUTION: was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group o

Algebra ->  Probability-and-statistics -> SOLUTION: was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group o      Log On


   



Question 61164: was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group of fifteen individuals needing a kidney transplant, find the probability that:
a) Less than ten will find a suitable donor among the registries of unrelated donors.
b) Exactly eight will find a suitable donor among the registries of unrelated donors.
c) At least fourteen will find a suitable donor among the registries of unrelated donors.
d) No more than five will find a suitable donor among the registries of unrelated donors.
e) Six or less will find a suitable donor among the registries of unrelated donors.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
was reported in a medical journal that about 70% of the individuals needing a kidney transplant find a suitable donor when they turn to registries of unrelated donors. In a group of fifteen individuals needing a kidney transplant, find the probability that:
-----------------
Comment: These are all binomial probability problems with p=0.7 and n=15.
I used a TI-83 to find the probabilities. You might have to use some other
calculator or your binomial tables.
--------------
a) Less than ten will find a suitable donor among the registries of unrelated donors.
P(0 ---------------
b) Exactly eight will find a suitable donor among the registries of unrelated donors.
P(X=8)=binompdf(15,0.7,8)=0.08
---------------
c) At least fourteen will find a suitable donor among the registries of unrelated donors.
P(X>=14)= 1-P(X<=13) = 1- binomcdf(15,0.7,13)= 1-0.964732...=0.035...
--------------
d) No more than five will find a suitable donor among the registries of unrelated donors.
P(X<=5)=binomcdf(15,0.7,5)=0.00365...
---------------
e) Six or less will find a suitable donor among the registries of unrelated donors.
P(X<=6)=binomcdf(15,0.7,6)=0.01524...
---------------
Cheers,
Stan H.