SOLUTION: Adam, Beth, and Cory (working together) can paint a room in 6 hours less time than Adam working alone, one hour less than Beth working alone, and one-half the time needed for Cory

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Adam, Beth, and Cory (working together) can paint a room in 6 hours less time than Adam working alone, one hour less than Beth working alone, and one-half the time needed for Cory       Log On


   



Question 611535: Adam, Beth, and Cory (working together) can paint a room in 6 hours less time than Adam working alone, one hour less than Beth working alone, and one-half the time needed for Cory working alone.
How long would it take Adam and Beth to paint the room working together (but without Cory)?

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x/a+x/b+x/c=1
a=x+6
b=x+1
c=2x
y/a+y/b=1
a=20/3
b=5/3
c=4/3
x=2/3
y=4/3
4/3 hour for Adam and Beth working together.