Question 611383: how do you graph x^2+y+2=0
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
Rewrite your equation with everything except the y in the RHS:
Compare this function to the vertex form of the parabola function:
^2\ +\ k)
which is a parabola with vertex at (h,k), focus at (h,k + p), axis of symmetry at  , and  -intercept at (0,k).
Since your equation has no 1st degree x term,  . By inspection,  hence  , so let's re-write again:
(x\ -\ 0)^2\ +\ (-2))
Now we can see that the vertex is at ) , the focus is at ) , the -intercept is the same as the vertex.
Next pick a couple of positive values (small positive integers) and substitute those values for  . Do the arithmetic to find the function value at those points. Plot the points to the right of the axis. Use the property of symmetry to find the corresponding points on the left side of the axis.
Finally draw a smooth curve through all of your points.
Or skip all of that stuff and use a graphing calculator.
John
My calculator said it, I believe it, that settles it
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