SOLUTION: I need to solve this equation in the interval [0, 2pi): square root of 2 * sin2x=0

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Question 611377: I need to solve this equation in the interval [0, 2pi):
square root of 2 * sin2x=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(2)*sin(2x) = 0

sin(2x) = 0

2x = arcsin(0)

2x = 0 or 2x = pi

x = 0 or x = pi/2