SOLUTION: How do I set this up? Four times the sum of twice the number and 7 exceeds the value of the number by 70. I know the first part is 4(2n+7) but then I get to the exceeds an

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Question 611020: How do I set this up?
Four times the sum of twice the number and 7 exceeds the value of the number by 70.
I know the first part is 4(2n+7) but then I get to the exceeds and I get very confused.
Found 2 solutions by richwmiller, ewatrrr:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
4(2n+7)=n+70

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi, 

Four times the sum of twice the number and 7 exceeds the value of the number by 70. 

Good work on the 4(2n+7)

Question states***

 4(2n+7) = n+%2B+70

Solving for n

 8n + 28 = n + 70

      7n = 42

       n = 6

CHECKING our Answer***

 4· (2·6 + 7) = 6 + 70 = 76