SOLUTION: Solve algebraically for all values of theta in the interval 0 degrees is < or equal to theta which is < 360 degrees. Express your answers to the nearest degree.
2sin^2 theta-4si
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-> SOLUTION: Solve algebraically for all values of theta in the interval 0 degrees is < or equal to theta which is < 360 degrees. Express your answers to the nearest degree.
2sin^2 theta-4si
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Question 610983: Solve algebraically for all values of theta in the interval 0 degrees is < or equal to theta which is < 360 degrees. Express your answers to the nearest degree.
2sin^2 theta-4sin theta = cos ^2 theta-2 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Solve algebraically for all values of theta in the interval 0 degrees is < or equal to theta which is < 360 degrees. Express your answers to the nearest degree.
2sin^2 theta-4sin theta = cos ^2 theta-2
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2sin^2x-4sinx=cos^2x-2
2sin^2x-4sinx=1-sin^2x-2
3sin^2x-4sinx+1=0
(3sinx-1)(sinx-1)=0
..
3sinx-1=0
sinx=1/3
x≈19º
or
sinx-1=0
sinx=1
x=90º
ans:
Theta≈19º and =90º
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