Question 61087This question is from textbook
: Please help. I am stuck with this problem.
Find all real or imaginary solution to the equation.
x^(-2)-9x^(-1)+18=0
It's x power negative 2 -9 power negative 1 +18=0
This question is from textbook
Answer by jai_kos(139)   (Show Source):
You can put this solution on YOUR website! Given x^ (-2)- 9x^ (-1) +18=0
Multiply the above equation by x^2, we get
x^2 * x^(-2) – 9x^(-1)* x^(2) + 18 x^2 = 0
1 – 9x + 18 x^2 = 0
Rewrite the above equation, we get
18x^2 – 9x + 1 = 0
This is the quadratic equation, we get
18x^2 – 6x – 3x +1 = 0
6x (3x -1) – 1(3x +1) = 0
(6x -1) (3x -1) = 0
(6x -1) = 0 or (3x -1) = 0
6x = 1 or 3x = 1
x = (1/6) or x = (1/3)
Therefore the value of “x” is (1/6) or (1/3)
|
|
|
