SOLUTION: What quantity of 60% acid solution must be mixed with 30% acid solution to produce 300mL of a 50% solution?

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Question 61054: What quantity of 60% acid solution must be mixed with 30% acid solution to produce 300mL of a 50% solution?
Answer by Earlsdon(6294) About Me  (Show Source):
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Let x = the number of ml of 60% acid solution to be added to (300-x) ml of 30% acid solution to obtain 300 ml of 50% acid solution. Change the percentages to their decimal equivalents.
0.6x + 0.3(300-x) = 0.5(300) Simplify and solve for x.
0.6x + 90 - 0.3x = 150
0.3x + 90 = 150
0.3x = 60
x = 200 ml