SOLUTION: a square and a a rectangle both have the same area. what is the numerical value of the rectangles perimeter if the rectangle has a length of 2x-3 and a width of x-2 and the square
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Question 610384: a square and a a rectangle both have the same area. what is the numerical value of the rectangles perimeter if the rectangle has a length of 2x-3 and a width of x-2 and the square has sides of x. thanks Answer by flame8855(424) (Show Source):
You can put this solution on YOUR website! (2x-3) ( x-2 ) = x^2
2x^2 -7x +6 =x^2
x^2-7x+6 = 0
(x-1)(x-6) = 0
x= 1
x = 6
so x =6
so 2x-3 =9
x-2 = 4
x =6
