SOLUTION: An urn contains seven red balls, four black balls, and six green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red bal
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-> SOLUTION: An urn contains seven red balls, four black balls, and six green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red bal
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Question 610343: An urn contains seven red balls, four black balls, and six green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red ball and a black ball will be selected? (Round your answer to three decimal places.) Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! An urn contains seven red balls, four black balls, and six green balls. If two balls are selected at random without replacement from the urn, what is the probability that a red ball and a black ball will be selected? (Round your answer to three decimal places.)
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total balls: 7+4+6 = 17
number of red balls: 7
number of black balls: 4
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7/17 * 4/16
7/17 * 1/4
7/68
0.10294
10.294%
