SOLUTION: solve by factoring. 1) x2-5x+6=0 2) 2x2-9x-5=0 3) 3x2+5x-2=0

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Question 6103: solve by factoring.
1) x2-5x+6=0
2) 2x2-9x-5=0
3) 3x2+5x-2=0
Found 2 solutions by Abbey, guapa:
Answer by Abbey(339) About Me  (Show Source):
You can put this solution on YOUR website!
1) x2-5x+6=0
(x-6)(x+1)=0
x=6, -1
2) 2x2-9x-5=0
(2x+1)(x-5) =0
x=-1/2, 5
3) 3x2+5x-2=0
(3x-1)(x+2)=0
x-1/3,-2

Answer by guapa(62) About Me  (Show Source):
You can put this solution on YOUR website!
1)
x%5E2-5x%2B6=0
Find the 2 middle terms which are the sum of -5x and a product of 6.
x%5E2-2x-3x%2B6=0
Now use the factoring by grouping method.
x%28x-2%29-3%28x-2%29=0
Now factor their common term
%28x-2%29%28x-3%29=0
Solve for x
(x-2)=0, x=2
(x-3)=0, x=3
2)
2x%5E2-9x-5=0
Proceed as showed above
2x%5E2-10x%2Bx-5=0
2x%28x-5%29%2B%28x-5%29=0
%28x-5%29%282x%2B1%29=0
Solve for x
x-5=0, x=5
(2x+1)=0, x= -1/2
3)
3x%5E2%2B5x-2=0
3x%5E2%2B6x-x-2=0
3x%28x%2B2%29-%28x%2B2%29=0
%28x%2B2%29%283x-1%29=0
Solve for x
x+2=0, x=-2
(3x-1)=0, x=1/3
Hope it helps