SOLUTION: How do you find the vertex, focus, and directrix in this formula? 4y^2+3x-16y+19=0 I'm pretty sure it is a parabola.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: How do you find the vertex, focus, and directrix in this formula? 4y^2+3x-16y+19=0 I'm pretty sure it is a parabola.      Log On


   

Question 610233: How do you find the vertex, focus, and directrix in this formula?
4y^2+3x-16y+19=0
I'm pretty sure it is a parabola.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
parabola
focus | (-19/16, 2)
vertex | (-1, 2)
semi-axis length | 3/16~~0.1875
focal parameter | 3/8~~0.375
eccentricity | 1
directrix | x = -13/16