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Question 610061: 1/16(y+4)^2 = x - 3
My teacher wants me to write this equation in standard form but I don't even know how to get started. What do I do first?
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! 1/16(y+4)^2 = x - 3
My teacher wants me to write this equation in standard form but I don't even know how to get started. What do I do first?
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First, you must recognize this is an equation of a parabola. Other conics are circles, ellipses and hyperbolas. You should be able to recognize the standard forms for each of these conics.
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Parabolas have two basic standard forms which apply to given problem:
x=A(y-k)^2+h, (h,k)=(x,y) coordinates of the vertex
or
(y-k)^2=4p(x-h), again, (h,k)=(x,y) coordinates of the vertex
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In this case, the second form applies, so we should rewrite given equation to look like this form:
1/16(y+4)^2 = x - 3
(y+4)^2=16(x-3) (Standard form of equation for parabola that opens rightwards)
vertex: (3,-4)
4p=16
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