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| Question 610056:  What are the asymptotes of the hyperbola given by the equation (y^2/1)-(x^2/121)=1?
 Answer by lwsshak3(11628)
      (Show Source): 
You can put this solution on YOUR website! What are the asymptotes of the hyperbola given by the equation (y^2/1)-(x^2/121)=1?
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 This is an equation of a hyperbola with vertical  transverse axis.
 Its standard form: (y-k)^2/a^2-(x-h)^2)/b^2=1, (h,k)=(x,y) coordinates of center
 For given equation: (y^2/1)-(x^2/121)=1
 center: (0,0)
 a^2=1
 a=1
 b^2=121
 b=√121=11
 ..
 Asymptotes are straight lines that go thru the center (0,0)
 Standard form of equation for straight lines: y=mx+b, m=slope, b=y-intercept
 For hyperbolas with vertical transverse axis:
 slopes of asymptotes=±a/b=1/11
 equations of asymptotes:
 y=±x/11+b
 since center is at (0,0), y-intercept, b=0
 equation of asymptotes:
 y=x/11
 and
 y=-x/11
 
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