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Question 609322: 16x^2-9y^2+96x+18y-135=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 16x^2-9y^2+96x+18y-135=0
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16x^2+96x -9y^2+18y = 135
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Do some factoring and complete the square:
16(x^2+6x+9) -9(y^2-2y+1) = 135 + 16*9 -9*1
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16(x+3)^2 -9(y-1)^2 = 270
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(x+3)^2/(270/16) - (y-1)^2/(270/9) = 1
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Hyperbola with center at (-3,1)
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Cheers,
Stan H.
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