SOLUTION: I am trying to figure out how to find x in: -4log base 2 (-2x)=-8 I know that it can be re-written as: log base 2 (-2x^-4)=-8 I think the next step would be to do: log base 2

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I am trying to figure out how to find x in: -4log base 2 (-2x)=-8 I know that it can be re-written as: log base 2 (-2x^-4)=-8 I think the next step would be to do: log base 2      Log On


   

Question 609063: I am trying to figure out how to find x in: -4log base 2 (-2x)=-8
I know that it can be re-written as: log base 2 (-2x^-4)=-8
I think the next step would be to do: log base 2 (-2) + log base 2 (x^-4) = -8
Is this right? How would I go about finding x?
Thank you!!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi



    ||Dividing both sides by -4

       2^2 = -2x

        -2 = x

 Rules Governing Logarithms                                    

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