SOLUTION: need help on this solve for x by completing the square; X^2-6x+13=0

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Question 60850: need help on this
solve for x by completing the square;
X^2-6x+13=0
Answer by jai_kos(139) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 -6x +13 = 0
This can be written as
(x^2 – 6x + 9)+ 4 = 0
(x-3)^2 + 4 =0
(x-3)^2 = - 4
Take the square root on both sides, we get
(x-3) = sqrt(-4), we get
x = sqrt(-4) + 3