Question 608365: I need help coming up with an equation and solution to the following problem:
A group of 21 friends each had the same 8 coins. altogether the group had $8.61. if each friend had onlyquarters, dimes, or pennies, how many pennies did they have altogether?
Thanks,
DR
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
If each of the 21 people had the same set of coins, then they each contributed the same amount of money, namely $8.61 divided by 21, or $0.41. The only way to make 41 cents out of 8 coins consisting of quarters, dimes, and pennies is 1 quarter, 1 dime, and 6 pennies. So, 6 pennies times 21...
John
My calculator said it, I believe it, that settles it
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