SOLUTION: This one has me bogged down.
I am attempting to graph and looking at the table.
Is this the correct way of looking at this equation?
The total profit (‘P’ in dollars) for
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-> SOLUTION: This one has me bogged down.
I am attempting to graph and looking at the table.
Is this the correct way of looking at this equation?
The total profit (‘P’ in dollars) for
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Question 60834This question is from textbook elementry and intermediate algebra
: This one has me bogged down.
I am attempting to graph and looking at the table.
Is this the correct way of looking at this equation?
The total profit (‘P’ in dollars) for sales of ‘x’ machines is given by P(x) = - 0.2 x^2 + 300x – 200. Find the following:
a. The profit if 500 machines are sold.
b. How many machines must be sold for maximum profit? This question is from textbook elementry and intermediate algebra
You can put this solution on YOUR website! a) P(x) = - 0.2 x^2 + 300x – 200
Substitute x = 500 machines.
P(500) = -0.2 x 500 ^ 2 + 300 x 500 - 200
P(500) = -0.2 x 250000 + 150000 - 200
P(500) = -50000 + 149800 = 99800
P(500) = $99800
Profit = $99800
b)The more machines are sold the more profit the company makes.
For every one machine that they sell they make $99.8 profit.
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