Question 607737: can you explain to me how i would solve this i am so confused.
Factor completely: -12x3y5 - 9x2y2 + 12xy3?
thank you !!
Found 3 solutions by ewatrrr, jim_thompson5910, Alan3354: Answer by ewatrrr(24785) (Show Source): Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Start with the given expression.
Factor out the GCF .
Now let's try to factor the inner expression
---------------------------------------------------------------
Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last coefficient is .
Now multiply the first coefficient by the last coefficient to get .
Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?
To find these two numbers, we need to list all of the factors of (the previous product).
Factors of :
1,2,4,8,16
-1,-2,-4,-8,-16
Note: list the negative of each factor. This will allow us to find all possible combinations.
These factors pair up and multiply to .
1*(-16) = -16
2*(-8) = -16
4*(-4) = -16
(-1)*(16) = -16
(-2)*(8) = -16
(-4)*(4) = -16
Now let's add up each pair of factors to see if one pair adds to the middle coefficient :
First Number | Second Number | Sum | 1 | -16 | 1+(-16)=-15 | 2 | -8 | 2+(-8)=-6 | 4 | -4 | 4+(-4)=0 | -1 | 16 | -1+16=15 | -2 | 8 | -2+8=6 | -4 | 4 | -4+4=0 |
From the table, we can see that there are no pairs of numbers which add to . So cannot be factored.
===============================================================
Answer:
So simply factors to
In other words, .
--------------------------------------------------------------------------------------------------------------
If you need more help, email me at jim_thompson5910@hotmail.com
Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you
Jim
--------------------------------------------------------------------------------------------------------------
Answer by Alan3354(69443) (Show Source):
|
|
|