| 
 
 
| Question 607408:  Where do i start to set this up?
 Suppose that 79,000 is invested at 5 and 1/2% interest, compounded quarterly .
 (a) find the function for the amount to which the investment grows after t  years.
 (b) find the amount of money in the account at t=0,3,7,10 years.
 (c)when will the amount of money reach $300,000?
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Suppose that 79,000 is invested at 5 and 1/2% interest, compounded quarterly . (a) find the function for the amount to which the investment grows after t years.
 ---
 A(t) = P(1+(r/n))^(nt)
 A(t) = 79000(1+(0.055/4))^(4t)
 -------------------------------------
 (b) find the amount of money in the account at t=0,3,7,10 years.
 Substitute each of those numbers for "t" to find A(t)
 --------------------------------------
 (c)when will the amount of money reach $300,000?
 Solve: 300,000 = 79000(1+(0.055/4))^(4t)
 3.7975 = (1.01375)^(4t)
 ---
 Take the log of both sides to get:
 4t*log(1.01375) = log(3.7975)
 4t = 97.71
 time = 24.4 years
 ======================
 Cheers,
 Stan H.
 
 | 
  
 | 
 |