SOLUTION: Graph the function f(x)= -x, X<3, 3x-4, x>= 3 a) fund the domain b) locate any intercepts c) graph the function d) find the range e) is f continuous

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Graph the function f(x)= -x, X<3, 3x-4, x>= 3 a) fund the domain b) locate any intercepts c) graph the function d) find the range e) is f continuous      Log On


   



Question 607288: Graph the function f(x)= -x, X<3,
3x-4, x>= 3
a) fund the domain
b) locate any intercepts
c) graph the function
d) find the range
e) is f continuous on its domain?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
a) The function is defined in two different ways for x<3 and for x%3E=3, but it is defined for all x, so the domain is all the real numbers.

b) For x<3, f(x)=-x is a straight line going through the origin, since f(0)=0, so you could say that the x-intercept and the y-intercept are (0,0).
In the other part of the function, for x%3E=3 ,
3x%3E=9 and f%28x%29=3x-4%3E=9-5=4%3E0 , so there are no intercepts (no x=0 and no y=0) in that part of the function.

c)

d) f(x)>-3 on both parts of the function, but there is no upper limit. Maybe you would describe the range as (-3,infinity), or maybe you are expected to use a different notation.

e) No. The function is obviously discontinuous at x=3. While it is continuous at all other points of its domain, it is not continuous at all points of the domain.