SOLUTION: Suppose that the length of a rectangle is 3 inches longer than the width and the perimeter of the rectangle is 78, set up an equation involving only W, the width of the rectangle?
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: Suppose that the length of a rectangle is 3 inches longer than the width and the perimeter of the rectangle is 78, set up an equation involving only W, the width of the rectangle?
Log On
Question 607284: Suppose that the length of a rectangle is 3 inches longer than the width and the perimeter of the rectangle is 78, set up an equation involving only W, the width of the rectangle? I am unsure how to make an equation with the width. Answer by alicealc(293) (Show Source):
You can put this solution on YOUR website! width = W
the length of a rectangle is 3 inches longer than the width:
length = 3 + W
perimeter of the rectangle is 78:
perimeter = 2*(length + width)
78 = 2*(3 + W + W)
78 = 2*(3 + 2W)
78 = 6 + 4W -> this is the equation
the solution will be:
78 - 6 = 4W
72 = 4W
W = 72/4 = 18
length = 3 + W = 3 + 18 = 21
so, the length of the rectangle is 21 inches and the width is 18 inches
(