SOLUTION: Help!Is this a problem with no solution? x + y + 2z = 7 2x + 2y + 4z = -6 x+y+2z = 1 Thanks so much!
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-> SOLUTION: Help!Is this a problem with no solution? x + y + 2z = 7 2x + 2y + 4z = -6 x+y+2z = 1 Thanks so much!
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Question 607176
:
Help!Is this a problem with no solution?
x + y + 2z = 7
2x + 2y + 4z = -6
x+y+2z = 1
Thanks so much!
Found 2 solutions by
jim_thompson5910, solver91311
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Answer by
jim_thompson5910(35256)
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Yes. We can see this if we let w = x+y+2z
The first equation then becomes w = 7 and the third equation becomes w = 1.
But this is a contradiction since w is both 7 and 1 at the same time.
Since this is not possible, there are no solutions.
Answer by
solver91311(24713)
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Show Source
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You can
put this solution on YOUR website!
Multiply equation 2 by
, then you have three equations with identical variable coefficients and different constants. Three mutually parallel lines. No point of intersection. No solution.
John
My calculator said it, I believe it, that settles it