SOLUTION: write the expression 1/3ln(x^2+1)-4ln3-5[ln(x-4)+lnx] as a single logarithm.

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Question 607043: write the expression 1/3ln(x^2+1)-4ln3-5[ln(x-4)+lnx] as a single logarithm.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
write the expression 1/3ln(x^2+1)-4ln3-5[ln(x-4)+lnx] as a single logarithm
1/3ln(x^2+1)-4ln3-5[ln(x-4)+lnx]
=1/3ln(x^2+1)-4ln3-5ln(x-4)-5lnx
=1/3ln(x^2+1)-(4ln3+5ln(x-4)+5lnx)
=ln[(x^2+1)^(1/3)/(3^4*(x-4)^5*x^5)]