Question 606856: I am a 4 digit number greater than 9,000.
My hundreds digit is twice my ones digit.
My ones digit is greater than my tens digit.
The sum of my digits is 20.
What number am I?
Answer by richard1234(7193)   (Show Source):
You can put this solution on YOUR website! Suppose the number is 9abc
We know that a = 2c, c > b. Also, 9+a+b+c = 20, so a+b+c = 11. We can assume c = 0, c = 1, c = 2, etc. and find all the possible triples (a,b,c):
c = 0 --> a = 0, b = 11
c = 1 --> a = 2, b = 8
c = 2 --> a = 4, b = 5
c = 3 --> a = 6, b = 2
The first three cases don't work, because b > 9, or b is greater than c. The third case does work, so (a,b,c) = (6,2,3) and the number is 9623.
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