SOLUTION: How do I solve: {{{4^(3x-1)=12}}}

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Question 606686: How do I solve:
4%5E%283x-1%29=12
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
4%5E%283x-1%29=12
If you have a variable in the exponent, we always want to take logs of both sides:
log%284%5E%283x-1%29%29=log%2812%29
Now we can bring down the exponent using our log rules:
%283x-1%29log%284%29=log%2812%29
And isolate for x
%283x-1%29=log%2812%29%2F%28log%284%29%29

I will leave the rest of the isolating up to you. (Don't forget that log of a number is just a number itself, so don't let that fool you)