SOLUTION: I am trying to write an equation for a parabola that has been sketched in my math book. I need it in standard form. x-h=a(y-k)^2. The points given in the graph are (-1,2), (0,1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I am trying to write an equation for a parabola that has been sketched in my math book. I need it in standard form. x-h=a(y-k)^2. The points given in the graph are (-1,2), (0,1      Log On


   



Question 606513: I am trying to write an equation for a parabola that has been sketched in my math book. I need it in standard form. x-h=a(y-k)^2.
The points given in the graph are (-1,2), (0,1), (0,3), (3,0), and (3,4).
I know that h=-1 and k=2 because those are the coordinates of the vertex, but I'm not sure what the 'a' represents or how to solve for it. Thanks!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I need it in standard form. x-h=a(y-k)^2.
The points given in the graph are (-1,2), (0,1), (0,3), (3,0), and (3,4).
I know that h=-1 and k=2 because those are the coordinates of the vertex, but I'm not sure what the 'a' represents or how to solve for it.
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Since you "know" that h = -1 and k = 2, you have:
x+1 = a(y-2)^2
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Use one of the points to solve for "a":
Using (3,4) you get:
3+1 = a(4-2)^2
4 = a(4)
a = 1
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Equation:
x+1 = (y-2)^2
x = (y-2)^2 - 1
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Cheers,
Stan H.
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