SOLUTION: how do you solve, 8sin^(theta)+2sin(theta)-1=0
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Question 605973
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how do you solve, 8sin^(theta)+2sin(theta)-1=0
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how do you solve, 8sin^(theta)+2sin(theta)-1=0
for 0 < x < 360º
8sin^2+2sin-1=0
(4sin-1)(2sin+1)=0
4sin-1=0
sinx=1/4
x≈14.48º and 165.52º
..
2sin+1=0
sinx=-1/2
x=210º and 330º