SOLUTION: Write the equation of the a is of symmetry, find the coordinates of the vertex of the graph of each function.
y= -(x-2)^2+1
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-> SOLUTION: Write the equation of the a is of symmetry, find the coordinates of the vertex of the graph of each function.
y= -(x-2)^2+1
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Question 605888: Write the equation of the a is of symmetry, find the coordinates of the vertex of the graph of each function.
y= -(x-2)^2+1 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Write the equation of the axis of symmetry, find the coordinates of the vertex of the graph of each function.
y= -(x-2)^2+1
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Given equation is that of a parabola that opens downwards;
Its standard form: y=-A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex
For given equation: y= -(x-2)^2+1
A=-1
vertex:(2,1)
axis of symmetry: x=2
see graph below:
(