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Question 60587This question is from textbook Glencoe
: Probability
I do not understand
A card is drawn from a deck of ten card numbered 1 - 10. The card is replaced in the deck and another card is drawn.
P(an odd number and then an even number)
P(two numbers greater than 4)
P(an odd number and then an even number)
P(5 and then a 3)
Please help me understand the concept....
This question is from textbook Glencoe
Answer by venugopalramana(3286)   (Show Source):
You can put this solution on YOUR website! Probability
I do not understand
A card is drawn from a deck of ten card numbered 1 - 10. The card is replaced in the deck and another card is drawn.
OK YOU GET PROBABILITY BY DIVIDING NUMBER OF SUCCESFULL OUT COMES
WITH TOTAL OF ALL POSSIBLE OUT COMES.
HERE THERE ARE 10 CARDS NUMBERED 1 TO 10.
HENCE THERE ARE IN TOTAL 10 POSSIBLE OUT COMES.LET US SEE SUCCESS REQUIREMENT AS ASKED FOR
P(an odd number and then an even number)
I DRAW ...
ODD NUMBER = THERE ARE 5 ODD NUMBERS = 1,3,5,7,9.
SO SUCCESSFULL OUT COMES = 5
PROBABILITY OF DRAWING ODD NUMBER = 5/10 = 1/2
II DRAW............
EVEN NUMBER...THERE ARE 5 EVEN NUMBERS = 2,4,6,8,10
SO SUCCESSFUL OUT COMES =5
PROBABILITY OF DRAWING EVEN NUMBER = 5/10=1/2
NOW PROBABILITY OF BOTH HAPPENING WHICH ARE 2 INDEPENDENT EVENTS = PRODUCT OF THEIR PROBABILITIES = (1/2)(1/2) = 1/4
GOT THE IDEA ..REST I AM GIVING ANSWERS CHECK UP
P(two numbers greater than 4)
5,6,7,8,9,10 = 6
(6/10)(6/10)=9/25
P(an odd number and then an even number)
(5/10)(5/10 =1/4
P(5 and then a 3)
5.....ONLY 1 WAY...SO P=1/10
3...ONLY 1 WAY SO...P=1/10
COMBINED PROBABILITY = (1/10)(1/10)=1/100
Please help me understand the concept....
You may edit the question. Maybe convert formulae to the same formula
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