SOLUTION: Please solve for T, BT^2 = F^3/Z, when B=2, F=3,and Z=4
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Question 605654
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Please solve for T, BT^2 = F^3/Z, when B=2, F=3,and Z=4
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lawdej(58)
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BT^2 = F^3/Z
2T^2=3^3/4
2T^2=27/4
T^2=27/8
T=+ or - square root of 27/8
T=+square root of 27/8 or T=-square root of 27/8
T=1.84 or T=-1.84