SOLUTION: In a particular neighborhood of 60 homes, 35 of the homes have children, 22 have pets and 15 have both. What is the probability that a random selected home in the neighborhood will
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Question 605438: In a particular neighborhood of 60 homes, 35 of the homes have children, 22 have pets and 15 have both. What is the probability that a random selected home in the neighborhood will
A. have children or pets.
B. Have neither children nor pets. Answer by solver91311(24713) (Show Source):
If 35 have children and 15 have both pets and children then 35 minus 15 = 20 have only children. Likewise, 7 have only pets.
So, 20 + 15 + 7 = 42 have either one or both, and 60 - 42 have neither. From those values you can calculate either question A or question B. Once you have either one, the probability of the other is 1 minus the probability of the first.
John
My calculator said it, I believe it, that settles it
