SOLUTION: In 2003 Sam was seven years older than his wife Jane. Jane was three times older than her son Barry who was twelve. 1) How old was Sam in 2003?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: In 2003 Sam was seven years older than his wife Jane. Jane was three times older than her son Barry who was twelve. 1) How old was Sam in 2003?       Log On


   

Question 605128: In 2003 Sam was seven years older than his wife Jane. Jane was three times older than her son Barry who was twelve.
1) How old was Sam in 2003?
2) How old will Jane be in 2009?
3) In 2009 what will be the difference between Sam and Barry's age?
Please show proper working
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In 2003 Sam was seven years older than his wife Jane. Jane was three times older than her son Barry who was twelve.
----
s = j+7
j = 3*12 = 36
========================

1) How old was Sam in 2003?
s = 36+7 = 43
--------------------------------------
2) How old will Jane be in 2009?
j = 36+6 = 42
---------------------
3) In 2009 what will be the difference between Sam and Barry's age?
Sam in 2009 = 43+6 = 49
Barry in 2009 = 12+6 = 18
Sam - Barry = 31 years
===============================
cheers,
Stan H.